Vedic Maths – Multiplication of any number by 11, 12, 13 … 19 the fast and simple way!
June 27, 2006
I learnt a nifty trick today. It has to do with the age old study of Vedic Maths So here it is: For Example if we have to multiply 943 * 13 (bcd * 1.x) 1. Rewrite the number as 0943 (Add a zero to the beginning of the number to be multiplied) 2. Multiply the last digit (d) with the last digit of the number (x) here we get 3 * 3 = ____9 3. Multiply the second last digit (c) with x and then add the previous digit. Here 4 * 3 = 12 + 3 = 15. Now write 5 and carry 1 forward so the answer becomes ___59 4. Multiply the next digit (b) with x and add the previous digit and the carry. Here 9 * 3 = 27 + 4 = 31 + 1 (Carry) = 32 again carry 3 and write 2 in the answer so we get __259 5. Multiply next digit (0 in this case) with x and add the previous digit and the carry. So we get 0 * 3 = 0 + 9 = 9 + 3 (Carry) = 12. Now we get the final answer which is 12259 Go ahead give it a try with 86926431 * 18
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1.
Anshu | July 16, 2006 at 5:18 am
Hi Harjeet !
Nice & simple ! That’s a great trick you learnt multiplying large numbers ! Do you have any books to refer to, or any links ?
2.
steven su | September 15, 2006 at 4:39 am
Use a calculato u genius
3.
Sujaritha | October 30, 2006 at 7:07 am
Hi Harjeet,
It was nice seeing that any number of digits when multiplied by 11–19 will be easy for the students seeing this blog. ALL THE BEST.
R.Sujaritha
4.
Gaurav Tekriwal | November 14, 2006 at 11:53 am
Hi Harjeet,
Nice article on vedic maths. U maywant to view our blog on the subject http://vedicmathsindia.blogspot.com
Do give in ur feedback and alo add it to ur blogroll.
wishes
Gaurav